3x^-4*y^5/(2x^3*y^-7)^-2

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Solution for 3x^-4*y^5/(2x^3*y^-7)^-2 equation: 


D( x )

x = 0

(2*x^3*y^-7)^-2 = 0

2*x^3*y^-7 = 0

x = 0

x = 0

(2*x^3*y^-7)^-2 = 0

(2*x^3*y^-7)^-2 = 0

1/4*x^-6*y^14 = 0 // : 1/4*y^14

x^-6 = 0

x należy do O

2*x^3*y^-7 = 0

2*x^3*y^-7 = 0

2*x^3*y^-7 = 0 // : 2*y^-7

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x^-4*y^5)/((2*x^3*y^-7)^-2) = 0

12*x^2*y^-9 = 0 // : 12*y^-9

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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